Question

Реши уровнения. 1)72/20-(х-12/20)=15/80 2)116/125- (41/125-х)=94/125
3) 4/40 + у+16/40=31/40+6/40
4)60/90-(6/90+х)=29/90​

Answer 1

1)

$\frac{72}{20} - (x - \frac{12}{20} ) = \frac{15}{80} \\ \frac{72}{20} - x + \frac{12}{20} = \frac{15}{80} \\ \frac{84}{20} - x = \frac{15}{80} \\ x = \frac{84}{20} - \frac{15}{80} \\ x = \frac{4 \times 84}{80} - \frac{15}{80} \\ x = \frac{336}{80} - \frac{15}{80} \\ x = \frac{321}{80} \\ x = 4 \frac{1}{8} \\ x = 4.125$

2)

$\frac{116}{125} - ( \frac{41}{125} - x) = \frac{94}{125} \\ \frac{116}{125} - \frac{41}{125} + x = \frac{94}{125} \\ \frac{75}{125} + x = \frac{94}{125} \\ x = \frac{94}{125} - \frac{75}{125} \\ x = \frac{19}{125 } \\ x = 0.152$

3)

$\frac{4}{40} + y + \frac{16}{40} = \frac{31}{40} + \frac{6}{40} \\ y + \frac{20}{40} = \frac{37}{40} \\ y = \frac{37}{40} - \frac{20}{40} \\ y = \frac{17}{40} \\ y = 0.425$

4)

$\frac{60}{90} - ( \frac{6}{90} + x) = \frac{29}{90} \\ \frac{60}{90} - \frac{6}{90} - x = \frac{29}{90} \\ \frac{54}{90} - x = \frac{29}{90} \\ x = \frac{54}{90} - \frac{29}{90} \\ x = \frac{25}{90}$