Question

Решите уравнение(с решением)

Answer 1

a

$\frac{3x - 16}{12} + 1 = \frac{x + 6}{4} - \frac{x + 3}{6} \: \: \: | \times 12 \\ 3x - 16 + 12 = 3(x + 4) - 2(x + 3) \\ 3x - 16 + 12 = 3x + 12 - 2x - 6 \\ 3x - 4 = x + 6 \\ 2x = 10 \\ x = 5$

б

$- {x}^{2} + 7x = 12 \\ - {x}^{2} + 7x - 12 = 0 \: \: \: | \times ( - 1) \\ {x}^{2} - 7x + 12 = 0 \\ D = {7}^{2} - 4 \times 12 = 49 - 48 = 1 \\ x_1 = \frac{7 + 1}{2} = 4 \\ x_2 = 3$

ответ: 3; 4