Question

выполнить действие...
вопрос жизни и смерти

Answer 1

-p

Пошаговое объяснение:

$=\frac{(p+1)(1-p)-1}{1-p}:\frac{p(p-1)-p^2}{p-1}=\frac{1-p^2-1}{1-p}*\frac{p-1}{p^2-p-p^2}=\\\frac{-p^2}{-(p-1)}*\frac{p-1}{-p}=-p$

Answer 2

$\displaystyle\bf \bigg(p+1-}\frac{1}{1-p} \bigg):\bigg(p-\frac{p^2}{p-1} \bigg)=\\\\\\\bigg(\frac{1-1-p^2}{1-p} \bigg)\times\bigg(\frac{p-1}{p^2-p^2-p}\bigg)=\\\\\\\frac{-p^2}{1-p}\times\frac{p-1}{-p} =\frac{-p^2}{1-p} \times\frac{-(1-p)}{-p} =\\\\\\\frac{-p^2}{1-p} \times\frac{1-p}{p} = \boxed{-p}$