Question

(3y+1)*(4y-5)-(6y-11)*(2y-7)=24

Answer 1

Пошаговое объяснение:

$(3y + 1) \times (4y - 5) - (6y - 11) \times (2y - 7) = 24 \\ 12y {}^{2} - 15y + 4y - 5 - (12y {}^{2} - 42y - 22y + 77) = 24 \\ 12y {}^{2} - 15y + 4y - 5 - (12y {}^{2} - 64y + 77) = 24 \\ 12y {}^{2} - 15y + 4y - 5 - 12y {}^{2} + 64y - 77 = 24 \\ - 15y + 4y - 5 + 64y - 77 = 24 \\ 53y - 5 - 77 = 24 \\ 53y - 82 = 24 \\ 5 3y = 24 + 82 \\ 53y = 106 \\ y = 2$

Answer 2

$y = 2$

Пошаговое объяснение:

$(3y + 1) \times (4y - 5) - (6y - 11) \times (2y - 7) = 24 \\ {12y}^{2} - 15y + 4y - 5 - (12 {y}^{2} - 42y - 22 + 77) = 24 \\ {12y}^{2} - 15y + 4y - 5 - {12}^{2} + 42y + 22y - 77 = 24 \\ 53y = 24 + 77 + 5 \\ 53y = 106 \\ y = 106 \div 53 \\ y = 2$