Question

решите) тема/многоэтажные дроби еще решение нужно

Answer 1

д)   $\frac{\frac{17}{100} -\frac{1}{10} }{10}= \frac{\frac{17}{100} -\frac{10}{100} }{10}= \frac{\frac{7}{100} }{10}=\frac{7}{100*10}= \frac{7}{1000}$

е)   $\frac{\frac{1}{2} +\frac{3}{4} }{\frac{1}{2} } =\frac{\frac{2}{4} +\frac{3}{4} }{\frac{1}{2} } =\frac{\frac{5}{4} }{\frac{1}{2} } =\frac{5*2}{4*1}= \frac{5}{2}= 2\frac{1}{2}$

ж)   $\frac{\frac{1}{4} +\frac{2}{3} }{2-\frac{1}{6} }= \frac{\frac{3}{12} +\frac{8}{12} }{\frac{12}{6} -\frac{1}{6} }= \frac{\frac{3}{12} +\frac{8}{12} }{\frac{11}{6} }= \frac{\frac{11}{12} }{\frac{11}{6} }= \frac{11*6}{12*11} =\frac{1}{2}$

з)    $\frac{\frac{7}{10} +\frac{3}{5} }{\frac{7}{10} +\frac{1}{2} }=\frac{\frac{7}{10} +\frac{6}{10} }{\frac{7}{10} +\frac{5}{10} }= \frac{\frac{13}{10}}{\frac{12}{10} }= \frac{13*10}{10*12}=\frac{13}{12} =1\frac{1}{12}$