Question

Решить выражение: (1/6+0.1+1/15): (1/6+0.1-1/15)*2.52 (0.5_1/3+0.25-1/5): (0,25-1/6)*7/13

Answer 1

1)(5/30+3/30+2/30):(5/30+3/30-2/30)*2.52=(10/30)*(30/6)*2.52=(10/6)*(252/100)=

=252/6=42

2)(150/300-100/300+75/300-60/300):(75/300-50/300)*7/13=(115/300)*(300/25)*7/13=

=(23/5)*(7/13)=161/65

Answer 2

$(\frac{1}{6}+\frac{1}{10}+\frac{1}{15}):(\frac{1}{6}+\frac{1}{10}-\frac{1}{15})*2.52 (\frac{5}{10}-\frac{1}{3}+\frac{5}{20}-\frac{1}{5}):(\frac{5}{20}-\frac{1}{6)*\frac{7}{13}$=$\frac{(\frac{10+6+4}{60}):(\frac{10+6-4}{60}*2.52}{(\frac{30-20+15-12}{60}):(\frac{15-10}{60})*\frac{7}{13}}$=$\frac{\frac{20}{60}:\frac{12}{60}*2.52}{\frac{13}{60}:\frac{5}{60}*\frac{7}{13}}$=$\frac{\frac{20}{12}*2.52}{\frac{13}{5}*\frac{7}{13}}$=$\frac{\frac{20}{12}*\frac{252}{100}}{\frac{13}{5}*\frac{7}{13}}$=$\frac{\frac{21}{5}}{\frac{7}{5}}$=$\frac{21}{5}*\frac{5}{7}=\frac{21}{7}=3$