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cerenkovvladimi
cerenkovvladimi
20.01.2020 03:47 •  Математика

В9 часов утра 2 катера отошли от пристани на озере в противоположных напровлениях.в 9 часов 30мин. растояние между ними было 39км 500м с какой скоростью шёл первый катер если скорость 2 45 км в час 20

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Ответ:
MasterDrenZik
MasterDrenZik
20.01.2020
45:2=22км500м за 30 мин 1 катер                                                                 39км500м-22км500м=17км за 30 мин катер                                            17*2=34 км/час  скорость 2 катера                                                                             (1час=60мин60:2=30мин)                                  
4,7(41 оценок)
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Ответ:
tseng7788
tseng7788
20.01.2020

Пошаговое объяснение:

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4,6(44 оценок)
Ответ:
domna0404
domna0404
20.01.2020

В решении.

Пошаговое объяснение:

Расстояние по трассе между двумя посёлками 1540 м. Из этих посёлков одновременно навстречу друг другу выехали два велосипедиста. Скорость первого равна 3 м/с, скорость второго 4 м/с. Какое расстояние будет между велосипедистами через 3 мин после начала движения? Через какое время после начала движения велосипедисты встретятся?

Формула движения: S=v*t

S - расстояние            v - скорость             t – время

3 минуты=60*3=180 секунд.

1)Найти расстояние 1 велосипедиста:

3*180=540 (м).

2)Найти расстояние 2 велосипедиста:

4*180=720 (м).

3)Какое расстояние будет между велосипедистами через 3 мин после начала движения?

1540 - (540+720)= 280 (м).

4)Через какое время после начала движения велосипедисты встретятся?

Общее расстояние 1540 м.

Общая скорость 3+4=7 (м/сек).

Общее время: 1540 : 7 = 220 (сек.)

4,5(21 оценок)
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