Question

Решите уравнения. 24х-3-(6+0,4х)=1 2х+(5-4х)=11

Answer 1

24x-3-(6+0,4x)=1
24x-3-6-0,4x=1
24x-0,4x=1+3+6
23,6x=10
$x= \frac{10}{23,6} = \frac{10}{1} :23 \frac{6}{10} = \frac{10}{1} : \frac{236}{10} = \frac{10}{1} * \frac{10}{236} = \frac{100}{236} = \frac{50}{118} = \frac{25}{59}$
$x= \frac{23}{59}$

2x+(5-4x)=11
2x+5-4x=11
2x-4x=11-5
-2x=6
$x= \frac{6}{-2}$
$x=-3$