Question

Решите неравенства: 4у+10≥2(1-у)+24

Answer 1

4y + 10 ≥ 2(1 - y) + 24

4y + 10 ≥ 2 - 2y + 24

4y + 2y ≥ 2 + 24 - 10

6y ≥ 16

y ≥ 16 : 6

$\displaystyle \[y\geqslant \frac{8}{3}\]$

ответ: $\displaystyle \[x\in\left[ {\frac{8}{3};\; +\infty}\right)\]$

Answer 2

$[ 2\frac{2}{3} ; +$∞ )

Пошаговое объяснение:

$4y+10\geq 2(1-y)+24;\\4y+10\geq 2-2y+24;\\4y+2y\geq 2+24-10;\\6y\geq 16;\\\\y\geq \frac{16}{6} ;\\\\y\geq \frac{8}{3} ;\\\\y\geq 2\frac{2}{3} .$