Question

Вычислите: 1)1/6+1/18•3/4 ; 2)4 11/48•6/7-1 4/9 ; 3) (2/3+5/8-11/12)•5 1/3 ; 4)15 4/7-4 3/8•(1 3/7-34/35) .

Answer 1

Пошаговое объяснение:

1)

$\frac{1}{6} +\frac{1}{18} *\frac{3}{4} =\frac{1}{6} +\frac{1*3}{18*4} =\frac{1}{6} +\frac{1}{24} =\frac{4}{24} +\frac{1}{24} =\frac{5}{24} .$

2)

$4\frac{11}{48} *\frac{6}{7} -1\frac{4}{9} =\frac{203}{48} *\frac{6}{7} -1\frac{4}{9} =\frac{203*6}{48*7} -1\frac{4}{9} =\frac{29}{8} -1\frac{4}{9} =3\frac{5}{8} -1\frac{4}{9} =\\\\3\frac{45}{72} -1\frac{32}{72} =2\frac{13}{72} .$

3)

$(\frac{2}{3} +\frac{5}{8} -\frac{11}{12} )*5\frac{1}{3} =(\frac{16}{24} +\frac{15}{24} -\frac{22}{24} )*5\frac{1}{3} =\frac{9}{24} *\frac{16}{3} =\frac{3*16}{8*3} =2.$

4)

$15\frac{4}{7} -4\frac{3}{8} *( 1\frac{3}{7} -\frac{34}{35} )= 15\frac{4}{7} -4\frac{3}{8} *(\frac{50}{35} -\frac{34}{35} )= 15\frac{4}{7} -4\frac{3}{8} *\frac{16}{35} =\\\\15\frac{4}{7} -\frac{35}{8} *\frac{16}{35} = 15\frac{4}{7} -2=13\frac{4}{7} .$