Question

Найдите координаты точек пересечения у=х^2-6х+4; у=2х-11

Answer 1

$\left \{ {{y= x^{2} -6x+4} \atop {y=2x-11}} \right. \\ 2x-11= x^{2} -6x+4 \\ x^{2} -6x+4-2x+11=0 \\ x^{2} -8x+15=0 \\ x=3 \\ x=5 \\ \left \{ {{x=3} \atop {y=2*3-11=-5}} \right. \\ \left \{ {{x=5} \atop {y=2+5-11=-1}} \right. \\ \left \{ {{x=3} \atop {y=-5}} \right. \\ \left \{ {{x=5} \atop {y=-1}} \right.$