Question

4.98-120.12: (8.008(4.0025-((1.12211-2x): 4.+0.03=1.01

Answer 1

х=0

Пошаговое объяснение:

4.98-120.12:(8.008(4.0025-((1.12211-2x):4.444)))+0.03=1.01​

x≠-3333/400

4.98-(3003:25):(1001:125*(1601/400-((112211:100000-2x):1111:250)))+0.03=1.01​

4.98-$\frac{3003}{25}$:($\frac{1001}{125}$*($\frac{1601}{400}$-(($\frac{112211}{100000}$-2x)*$\frac{250}{1111}$)))+0.03=1.01​

4.98-$\frac{3003}{25}$:($\frac{1001}{125}$*($\frac{1601}{400}$-(($\frac{101}{400}$-$\frac{500}{1111}$x)))+0.03=1.01​

4.98-$\frac{3003}{25}$:($\frac{1001}{125}$*($\frac{1601}{400}$-$\frac{101}{400}$+$\frac{500}{1111}$x))+0.03=1.01​

4.98-$\frac{3003}{25}$:($\frac{1001}{125}$*($\frac{15}{4}$+$\frac{500}{1111}$x))+0.03=1.01​

4.98-$\frac{3003}{25}$:($\frac{3003}{100}$+$\frac{364}{101}$x))+0.03=1.01​

4.98-$\frac{3003}{25}$:$\frac{303303+36400x}{10100}$+0.03=1.01​

4.98-$\frac{3003}{25}$*$\frac{10100}{303303+36400x}$+0.03=1.01​

4.98-3003*$\frac{404}{91*(3333+400x)}$+0.03=1.01​

4.98-33*$\frac{404}{3333+400x}$+0.03=1.01​

4.98-$\frac{13332}{3333+400x}$+0.03=1.01​

5.01-$\frac{13332}{3333+400x}$=1.01​

$\frac{501}{100}$-$\frac{13332}{3333+400x}$=$\frac{101}{100}$​

-$\frac{13332}{3333+400x}$=$\frac{101}{100}$​-$\frac{501}{100}$

-$\frac{13332}{3333+400x}$=-4

13332=(3333+400x)*4

13332=13332+1600x

0=1600x

x=0