Question

51/3: 6 2/5+(12: 3 3/5-2/3)*2/3+7 2/5

Answer 1

$5\tt\displaystyle\frac{1}{3}:6\frac{2}{5}+(12:3\frac{3}{5}-\frac{2}{3})*\frac{2}{3}+7\frac{2}{5}=10\frac{1}{90}$

$1)12:3\tt\displaystyle\frac{3}{5}=12:\frac{18}{5}=\frac{12*5}{80}=\frac{10}{3}$

$2)\tt\displaystyle\frac{10}{3}-\frac{2}{3}=\frac{8}{3}$

$3)5\tt\displaystyle\frac{1}{3}:6\frac{2}{5}=\frac{16}{3}:\frac{32}{5}=\frac{16}{3}*\frac{5}{32}=\frac{5}{6}$

$4)\tt\displaystyle\frac{8}{3}*\frac{2}{3}=\frac{16}{9}$

$5)\tt\displaystyle\frac{5}{6}+\frac{16}{9}=\frac{15+32}{18}=\frac{47}{18}=2\frac{11}{18}$

$6)2\tt\displaystyle\frac{11}{18}+7\frac{2}{5}=2\frac{55}{90}+7\frac{36}{90}=9\frac{91}{90}=10\frac{1}{90}$