Відповідь:
Покрокове пояснення:
Случайная величина Х может принимать значения 0; 1; 2; 3; 4
р1=0.3. q1=0.7
р2=0.4. q2=0.6
р3=0.6. q3=0.4
р4=0.8. q4=0.2
P(0)=q1×q2×q3×q4=0.7×0.6×0.4×0.2=0.0336
P(1)=p1×q2×q3×q4+q1×p2×q3×q4+q1×q2×p3×q4+q1×q2× q3×p4=0.3×0.6×0.4×0.2+0.7×0.4×0.4×0.2+0.7×0.6×0.6×0.2+0.7×0.6×0.4×0.8=0.2216
P(3)=0.3×0.4×0.6×0.2+0.7×0.4×0.6×0.8+0.3×0.6×0.6×0.8+0.3×0.4×0.4×0.8=0.2736
P(4)=0.3×0.4×0.6×0.8=0.0576
P(2)=1-(P(0)+P(1)+P(3)+P(4))=0.4136
X. P. F(x)
0. 0.0336. 0.0336
1. 0.2216. 0.2552
2. 0.4136. 0.6688
3. 0.2736. 0.9424
4. 0.0576. 1
F(x)=0 для Х<0
F(x)=1 для Х>4
Графиком F(x) будет ступенчетий график
Мх=0×0.0336+1×0.2216+2×0.4136+3×0.2736+4×0.0576=2.1
М(х^2)=0×0.0336+1×0.2216+4×0.4136+9×0.2736+ 16×0.0576=5.26
Dx=M(x^2)-(Mx)^2=5.26-(2.1)^2=0.85
√D=√(0.85)= 0.9219544457
2) = 3 9/30 - 1 14/30 = 2 39/30 - 1 14/30 = 1 25/30 = 1 5/6