Question

Разложите на множители выражение -0.027x^6+y^3/64

Answer 1

-0,027x^6+y^3/64=(-0,3)x^2)^3+(y/4)^3=(-0,3x^2+y/4)(0,09x^4-(-0,3x^2y/4)+y^2/16)=

=(0,25y-0,3x^2)(0,09x^4+0,075x^2y+0,0625y^2)

Answer 2

$-0,027x^{6}+\frac{y^{3}}{64}=-\frac{27}{1000}x^{6}+\frac{y^{3}}{64}=((-\frac{3}{10})x^{2})^{3}+(\frac{y}{4})^{3}=$
$(-\frac{3}{10}x^{2}+\frac{y}{4})(\frac{9}{100}x^{4}-(-\frac{3}{10}x^{2}\cdot\frac{y}{4})+\frac{y^{2}}{16})=$
$(-\frac{3}{10}x^{2}+\frac{1}{4}y)(\frac{9}{100}x^{4}+\frac{3}{40}x^{2}y+\frac{y^{2}}{16})= (\frac{1}{4}y-\frac{3}{10}x^{2})(\frac{9}{100}x^{4}+\frac{3}{40}x^{2}y+\frac{y^{2}}{16})$
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$-0,027x^{6}+\frac{y^{3}}{64}=-0,027x^{6}+0,015625y^{3}=(-0,3)x^{2})^{3}+(0,25y)^{3}=(-0,3x^{2}+0,25y)(0,09x^{4}-(-0,3x^{2}\cdot0,25y)+0,0625y^{2})=$
$(-0,3x^{2}+0,25y)(0,09x^{4}-(-0,075x^{2}y)+0,0625y^{2})=(0,25y-0,3x^2)(0,09x^{4}+0,075x^{2}y+0,0625y^{2})$