Question

Cократите дробь: x^2-y^2 3x-2x^2+3y-2xy решите плз

Answer 1

$\frac{x^2-y^2}{3x-2x^2+3y -2xy} = \frac{(x-y)(x+y)}{(3x+3y) +(-2x^2-2xy)} = \\ \\ = \frac{(x-y)(x+y)}{3(x+y) -2x(x+y)} = \frac{(x-y)(x+y)}{(3-2x)(x+y)} = \frac{x-y}{3-2x}$