Question

(1цел,18/25-9,12-7,4(-6цел1/3))/5цел1/3

Answer 1

$(1 \frac{18}{25} -9,12-7,4(-6 \frac{1}{3} ))/5 \frac{1}{3}$
По действиям:
1⇒$7,4(-6 \frac{1}{3} )=7 \frac{4}{10}* (-6 \frac{1}{3} )=- \frac{74*19}{10*3} =- \frac{1406}{30} =- \frac{703}{15}$
2⇒$1 \frac{18}{25} -9,12=1 \frac{18}{25}-9 \frac{12}{100} = \frac{43}{25}- \frac{912}{100}= \frac{172-912}{100}=- \frac{740}{100} = -\frac{74}{10}$
3⇒$-\frac{74}{10}-(- \frac{703}{15})=-\frac{74}{10}+ \frac{703}{15}= \frac{-222+1406}{30}= \frac{1184}{30}= \frac{592}{15}$
4⇒$\frac{592}{15}:5 \frac{1}{3}= \frac{592}{15}: \frac{16}{3}= \frac{592*3}{15*16}= \frac{37}{5}=7,4$