Question

Решить неравенства,. номер 1234

Answer 1

$1)10 < 3x + 4 < 19 \\ 10 - 4 < 3x < 19 - 4 \\ 6 < 3x < 15 \\ 6 \div 3 < x < 15 \div 3 \\ 2 < x < 5 \\ 2) - 5 < 9 + 2x < 17 \\ - 5 - 9 < 2x < 17 - 9 \\ - 14 < 2x < 12 \\ - 14 \div 2 < x < 12 \div 2 \\ - 7 < x < 6 \\ 3)4 < \frac{3x + 2}{2} < 7 \\ 4 \times 2 < 3x + 2 < 7 \times 2 \\ 8 < 3x + 2 < 14 \\ 8 - 2 < 3x < 14 - 2 \\ 6 < 3x < 12 \\ 6 \div 3 < x < 12 \div 2 \\ 2 < x < 6 \\ 4) - 3 < \frac{x - 8}{4} < 1 \\ - 3 \times 4 < x - 8 < 1 \times 4 \\ - 12 < x - 8 < 4 \\ - 12 + 8 < x < 4 + 8 \\ - 4 < x < 12$