Question

Выполнить деление: 1)х2-10х+25 х-5 : х2-100 х-10 2)а2-1 а2+2а+1 : а-8 а-8 3)аb+b2 ab+a2 : 8b 2a ,буду !

Answer 1

$1. \frac{ x^{2} -10x+25}{ x^{2} -100} : \frac{x-5}{x-10} = \frac{(x-5)^2}{(x-10)(x+10)} \frac{(x-10)}{(x-5)}= \frac{x-5}{x+10}$
$2) \frac{ a^{2}-1 }{a-8}: \frac{ a^{2}+2a+1 }{a-8}=\frac{ (a-1)(a+1) }{(a-8)}* \frac{(a-8)}{ (a+1)^{2} }= \frac{a-1}{a+1}$
$3) \frac{ab+ b^{2} }{8b}: \frac{ab+ a^{2} }{2a} = \frac{b(a+b)}{8b}* \frac{2a}{a(b+a)} = \frac{1}{4}$