Question

3(в степени 2-/3) в степени х+1> 26/3

Answer 1

$3^{2-x} - \frac{1}{3} ^{x+1} \ \textgreater \ \frac{26}{3}$
$3^{2-x} - 3^{-x-1} \ \textgreater \ \frac{26}{3}$
$3^{3-x} - 3^{-x} \ \textgreater \ 26$
$3^{-x} ( 3^{3}-1 )\ \textgreater \ 26$
$3^{-x} *26\ \textgreater \ 26$
$3^{-x}\ \textgreater \ 1$
$3^{-x} \ \textgreater \ 3^{0}$
$-x\ \textgreater \ 0$
$x\ \textless \ 0$