Question

Найдите значение выражения: 1) (3/16+a)-3/8, a=5/12 2) (b+5/6)-3/4, b=11/12 3) (4/15+5/8)-c, c=3/5 4) (1/5+d)-9/20, d=13/16. поставлю лучшим кто будет первым! ?

Answer 1

1)
$( \frac{3}{16}+a)- \frac{3}{8} = \frac{3}{16}+a- \frac{6}{16}=a- \frac{3}{16}$
$a= \frac{5}{12}$
$\frac{5}{12} - \frac{3}{16} = \frac{20}{48} - \frac{9}{48} = \frac{11}{48}$

2)
$( b+\frac{5}{6})- \frac{3}{4} =b+ \frac{10}{12}- \frac{9}{12}=b+\frac{1}{12}$
$b= \frac{11}{12}$
$b+ \frac{1}{12}= \frac{11}{12} + \frac{1}{12} =1$

3)
$( \frac{4}{15}+ \frac{5}{8})-c = \frac{32}{120}+ \frac{75}{120}-c= \frac{107}{120}-c$
$c= \frac{3}{5}$
$\frac{107}{120}-c = \frac{107}{120}- \frac{3}{5} = \frac{107}{120}- \frac{72}{120} = \frac{35}{120} = \frac{7}{24}$

4)
$( \frac{1}{5}+d)- \frac{9}{20} = \frac{4}{20} +d- \frac{9}{20}=d- \frac{5}{20}=d- \frac{1}{4}$
$d= \frac{13}{16}$
$\frac{13}{16} - \frac{1}{4} = \frac{13}{16} - \frac{4}{16} = \frac{9}{16}$