Question

Решите уравнение: 1) x+4 4/19=6 2/19; 2)25-x =8 3/14; 3) 32-x=9 18/35. 60

Answer 1

$\displaystyle \tt 1) \: x+4\frac{4}{19}=6\frac{2}{19}\\\displaystyle \tt x+\frac{80}{19}=\frac{116}{19}\\\displaystyle \tt x=\frac{116}{19}-\frac{80}{19}\\\displaystyle \tt x=\frac{36}{19}\\\displaystyle \tt \boxed{\bold{x=1\frac{17}{19}}}$

$\displaystyle \tt 2) \: 25-x=8\frac{3}{14}\\\displaystyle \tt 25-x=\frac{115}{14}\\\displaystyle \tt -x=\frac{115}{14}-25\\\displaystyle \tt -x=-\frac{235}{14}\\\displaystyle \tt x=\frac{235}{14}\\\displaystyle \tt \boxed{\bold{x=16\frac{11}{14}}}$

$\displaystyle \tt 3) \: 32-x=9\frac{18}{35}\\\displaystyle \tt 32-x=\frac{333}{35}\\\displaystyle \tt -x=\frac{333}{35}-32\\\displaystyle \tt -x=-\frac{787}{35}\\\displaystyle \tt x=\frac{787}{35}\\\displaystyle \tt \boxed{\bold{x=22\frac{17}{35}}}$