Question

Решите 2 ! 20 решать по ! & 1 1)4,2*(-7)-9,3: (5,8-8,9) ,2-3,91: (2,3)): (-0,01): (-0,4) & 2 (-4/15+7/12): (-38/45) (11//24)): (-5целых 7/12) (-11/18+29/45): (35/54-19/27) -4целых 1/7+2целых 1/4*(-11целых 2/,4): 9/35)

Answer 1

№1
1) $4.2*(-7)-9.3:(5.8-8.9)=-29.4-9.3:(-3.1)=-29.4+3=$$-26.4$
2) $(-4.2-3.91:2.3):(-0.01):(-0.4)=(-4.2-1.7):(-0.01):(-0.4)=$$=-5.9:(-0.01):(-0.4)=590:(-0.4)=-1475$

№2
1) $(- \frac{4}{15} + \frac{7}{12} ):(- \frac{38}{45} )=(- \frac{16}{60} + \frac{35}{60} ):(- \frac{38}{45} )= \frac{19}{60} *(- \frac{45}{38})=- \frac{3}{8}$
2) $( \frac{11}{16} -(- \frac{17}{24} )):(-5 \frac{7}{12} )=( \frac{33}{48}+ \frac{34}{48}):(-5 \frac{7}{12} )= \frac{67}{48}:(-\frac{67}{12})= \frac{67}{48}*( -\frac{12}{67})=$$=- \frac{1}{4}$
3) $(- \frac{11}{18} + \frac{29}{45} ):( \frac{35}{54} - \frac{19}{27})=(- \frac{55}{90} + \frac{58}{90} ):( \frac{35}{54} - \frac{38}{54})= \frac{3}{90} :(- \frac{3}{54})} =$$=\frac{1}{30} *(- 18) =- \frac{3}{5}$
4) $-4\frac{1}{7} +2\frac{1}{4} *(-11 \frac{2}{9} -(-5.4): \frac{9}{35} )=-4\frac{1}{7} +2\frac{1}{4} *(-11 \frac{2}{9} +5.4: \frac{9}{35} )=$$-4\frac{1}{7} +2\frac{1}{4} *(-11 \frac{2}{9} + \frac{27}{5} : \frac{9}{35} )=-4\frac{1}{7} +2\frac{1}{4} *(-11 \frac{2}{9} + \frac{27}{5}* \frac{35}{9} )=$$=-4\frac{1}{7} +\frac{9}{4} *(-11 \frac{2}{9} +21 )=-4\frac{1}{7} +\frac{9}{4} *9 \frac{7}{9} =-4\frac{1}{7} +\frac{9}{4} * \frac{88}{9} =-4\frac{1}{7} +22=$$=17 \frac{6}{7}$