Log0,5(x^2-27) log0,5 6x in e^3 буду . - id750353420210815 от saponovadasha 15.08.2021 23:24

Question

Математика: Log0,5(x^2-27) log0,5 6x in e^3 буду .

saponovadasha · Accepted Answer

А₃ = а₁ +2d 1.1 = a₁ + 2d a₁ = 1.1-2d a₁ = 1.1-2d a₇ = a₁ + 6d 2.3 = a₁ +6d 2.3 = 1.1-2d +6d 2.3-1.1 = 4d ₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋ a₁ = 1.1-2d a₁ = 1.1-2d a₁ = 1.1-2*0.3 = 0.5 1.2 = 4d d = 0.3 d =0.3 s₁₀ = ((2a₁ + d(n-1))*n)/ 2 = (2*0.5 + 0.3(10-1)) *10) /2 = (1+2.7*10)/2 = = (1+27)/2 = 28/2 = 14 s₁₀ = 14...

Log0,5(x^2-27)> log0,5 6x in e^3 буду .

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