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илья1968
илья1968
08.09.2021 21:26 •  Математика

Решите пример (2,727: (-0,9)+1,,3)+1,58): 4,8

👇
Ответ:
stars28082003
stars28082003
08.09.2021
(2,727:(-0,9)+1,9-(-5,3)+1,58):4,8≈1,185
2,727:(-0,9)= -3,03
- 3,03+1,9 = - 1,13
(-1,13)-(-5,3)=(-1,13)+5,3= 4,17
4,17+1,52=5,69
5,69:4,8=⁵⁶⁹/₁₀₀÷⁴⁸/₁₀=⁵⁶⁹/₁₀₀×¹⁰/₄₈=⁵⁶⁹ˣ¹⁰/₁₀₀ₓ₄₈=⁵⁶⁹/₄₈₀=1⁸⁹/₄₈₀≈1,185
4,7(54 оценок)
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Ответ:
ROMMIT2
ROMMIT2
08.09.2021

Пошаговое объяснение:

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4,4(68 оценок)
Ответ:
анна2255
анна2255
08.09.2021

Смотрите.

1) Обозначаем t — сколько времени они шли в первый день, тогда (t-1) — сколько во второй.

2) Теперь следующее соотношение — про 6 километров. Пускай в первый день они км, а во второй день — s2, тогда нам дано:

s1-s2=6.

3) Вспоминая, что расстояние=время*скорость (s=v*t), подставляем в эту формулу вместо s1 и s2:

(3,5*t)-(3*(t-1))=6.

Упрощаем:

3,5t-3t+3=6;

0,5t=3;

t=6.

ответ: Таким образом, в первый день они шли 6 часов. Во второй день — 6-1=5 (часов во второй день — 3*5 = 15 (км)

Пошаговое объяснение:

4,7(15 оценок)
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