) где p полупериметр = (25+25+40):2=45 , а в и с стороны треугольника. подставляя значения в ф-лу получаем что радиус равен 6.(6)
1) 2ab - 3b при а = 2, b = 3:
2 * 2 * 3 - 3 * 3 = 12 - 9 = 3.
2) 3ab + 2ab при а = -1, b = 1:
3 * (-1) * 1 + 2 * 1 = -3 + 2 = -1.
3) ab - 4a при а = 2, b = -1:
2 * (-1) - 4 * 2 = -2 - 8 = -10.
4) 2a + 3ab при а = -1, b = 0:
2 * (-1) + 3 * (-1) * 0 = -2 +0 = -2.
5) ba - 3a +1 при а = 1, b = 2:
2 * 1 - 3 * 1 + 1 = 2 - 3 + 1 = 0.
6) 2ab + 3ab - 1 при а = 2, b = -1:
2 * 2 * (-1) + 3 * (-1) - 1 = -4 -3 -1 = -8.
7) a - 4ab + 2 при а = 0, b = -3:
0 - 4 * 0 * (-3) + 2 = 0 +0 + 2 = 2.
8) a + 2b - ab при а = 1, b = -3:
1 + 2 * (-3) - 1 * (-3) = 1 - 6 + 3 = -2.
9) ab - 4a - 2b при а = 4, b = -1:
4 * (-1) - 4 * 4 - 2 * (-1) = -4 -16 + 2 = -18.
10) a + ab + b при а = 1, b = -1:
1 + 1 * (-1) + (-1) = 1 - 1 - 1 = -1.
−427∗316−313∗133=−37
1) -\frac{27}{4} * \frac{16}{3} = -\frac{36}{1} = -36−427∗316=−136=−36
2) \frac{13}{3} * \frac{3}{13} = 1313∗133=1
3) -36-1 = -37
-\frac{13}{6} + \frac{1}{4} * (-\frac{24}{11}) = -2\frac{47}{66}−613+41∗(−1124)=−26647
1) \frac{1}{4} * (-\frac{24}{11}) = -\frac{6}{11}41∗(−1124)=−116
2) -\frac{13}{6} - \frac{6}{11} = -\frac{143}{66} - \frac{36}{66} = -\frac{179}{66} = -2\frac{47}{66}−613−116=−66143−6636=−66179=−26647
\frac{27}{7} * (-\frac{7}{3}) - \frac{8}{9} * (-\frac{15}{8}) = -7\frac{1}{3}727∗(−37)−98∗(−815)=−731
1) \frac{27}{7} * (-\frac{7}{3}) = -9727∗(−37)=−9
2) \frac{8}{9} * (-\frac{15}{8}) = -\frac{5}{3}98∗(−815)=−35
3) -\frac{27}{3} + \frac{5}{3} = -\frac{22}{3} = -7\frac{1}{3}−327+35=−322=−731
-\frac{67}{8} + \frac{113}{16} * (-\frac{72}{29}) = -25\frac{211}{232}−867+16113∗(−2972)=−25232211
1) \frac{113}{16} * (-\frac{72}{29}) = \frac{1017}{58}16113∗(−2972)=581017
2) (-\frac{67}{8}) - \frac{1017}{58} = -\frac{1943}{232} - \frac{4068}{232} = -\frac{6011}{232} = -25\frac{211}{232}(−867)−581017=−2321943
