Question

Все за уравнение (x-2)(x-3)-x^2=(x+2)(x+4)+x^2-(x-1)^2

Answer 1

X^2-3x-2x+6-x^2=x^2+4x+2x+8+x^2-(x^2-2x+1)
-5x+6=2x^2+6x+8-x^2+2x-1
-5x+6=x^2+8x+7
x^2+13x+1=0
D=169-4=165
x1=(-13+sqrt(165))/2
x2=(-13-sqrt(165))/2

Answer 2

$(x-2)(x-3)-x^2=(x+2)(x+4)+x^2-(x-1)^2;\\ x^2-5x+6-x^2=x^2+6x+8+x^2-x^2+2x-1;\\ -5x+6=x^2+6x+8+2x-1;\\ x^2+13x+1=0;\\ D=13^2-4\cdot 1=169-4=165;\\ x_{1,2}=\frac{-13\pm \sqrt{165}}{2}.$