Question

Разложите квадратный трехчлен на линейные множители 3х(в 2 степени)-4x-7 ! ✌

Answer 1

3x²-4x-7 =3(x²-4/3x-7/3) = 3(x-7/3)(x+1)

Answer 2

$3 {x}^{2} - 4x - 7 = 0\\ d = 16 + 4 \times 3 \times 7 = 16 + 84 = 100 0 \\ x1 = \frac{4 + 10}{6} = \frac{14}{6} = \frac{7}{3} \\ x2 = \frac{4 - 10}{6} = \frac{ - 6}{6} = - 1$
$3 {x}^{2} - 4x - 7 = 3(x - \frac{7}{3} )(x + 1) = (3x - 7)(x + 1)$