1)x = ±2 3) x = ±3 5) x = ±1/7
2)y = ±3 4) y = ±2 6) y = ±1
Пошаговое объяснение:
1)[x] + 3 = 5 2)[y] - 2 =1 3) [2x] + 3 = 9
[x] = 5 - 3 [y] = 1+2 [2x] = 9 - 3
[x] = 2 [y] = 3 [2x] = 6
x = ±2 y = ±3 [x] = 6/2
[x] = 3
x = ±3
4) [5y] - 4 = 6
[5y] = 6+4
[5y] = 10
[y] = 10/5
[y] = 2
y = ±2
5)3/7 + [4x] = 1
[4x] = 1 - 3/7
[4x] = 4/7
[x] = 4/7 : 4
[x] = 1/7
x = ±1/7
6)4 + [3y] = 7
[3y] = 7 - 4
[3y] = 3
[y] = 3/3
[y] = 1
y = ±1
