Question

Х^2+2х-2=0 там а=1 b=2 c=-2 k=1 а дальше не знаю

Answer 1

D = (-2)² - 4* 1*(-2) = 4+8 = 12
x1 = -2+√12/2 = -1+√3
x2 = -2 - √12/2 = -1-√3

Answer 2

x²+2x-2 = 0.   a=1, b=2, c=-2.

D = b² - 4ac
D = 2² - 4·1·(-2) = 4 + 8 = 12.

$x_1_,_2 = \dfrac{-b б \sqrt{D}}{2a}. \\ \\ \\ x_1 = \dfrac{-2+ \sqrt{12}}{2 \cdot 1} = \dfrac{-2 + \sqrt{4\cdot3}}{2\cdot1} = \dfrac{-2+ 2\sqrt{3}}{2} = -1 + \sqrt{3}. \\ \\ x_2 = \dfrac{-2 - \sqrt{12}}{2 \cdot 1} = \dfrac{-2 - \sqrt{4\cdot3}}{2\cdot1} = \dfrac{-2 - 2\sqrt{3}}{2} = -1 - \sqrt{3}. \\ \\ \\ \boxed{ \boldsymbol{OTBET:-1 - \sqrt{3}; \ \ -1 + \sqrt{3}} }$