Question

Решите уравнение а) 6 (12+x) = 64 + 2x; б)0,7 + 0,3 (x+2) = 0? 4 (x - 3)

Answer 1

А)
$6(12 + x) = 64 + 2x \\ 72 + 6x = 64 + 2x \\ 6x - 2x = 64 - 72 \\ 4x = - 8 \\ x = - 2$
б)
$0.7 + 0.3(x + 2) = 0.4(x - 3) \\ 0.7 + 0.3x + 0.6 = 0.4x - 1.2 \\ 0.3x - 0.4x = - 1.2 - 0.7 - 0.6 \\ - 0.1x = - 2.5 \\ x = \frac{ - 2.5}{ - 0.1} \\ x = 25$