Question

Найдите значение функции y=3-4x при x =10; -6; 0; 1,6

Answer 1

$y = 3 - 4x \\ x = 10 \\ y = 3 - 4 \times 10 = 3 - 40 = - 37$

$y = 3 - 4x \\ x = - 6 \\ y = 3 - 4 \times ( - 6) = 3 + 24 = 27$

$y = 3 - 4x \\ x = 0 \\ y = 3 - 4 \times 0 = 3 - 0 = 3$

$y = 3 - 4x \\ x = 1 \\ y = 3 - 4 \times 1 = 3 - 4 = - 1$

$y = 3 - 4x \\ x = 6 \\ y = 3 - 4 \times 6 = 3 - 24 = - 21$

Answer 2

При x=10

y=3-4(10)=3-40=-37

При x=-6

y=3-4(-6)=3+24=27

При x=0

y=3-4(0)=3-0=3

При x=1,6

y=3-4(1,6)=3-6,4=-3,4