Question

1. выполните действие:
a) 6/x^2+3x-2/x
б) 5b/a^2-ab * a^2-b^2/10b^2

Answer 1

$1a)\; \; \frac{6}{x^2+3x}-\frac{2}{x}=\frac{6}{x(x+3)}-\frac{2}{x}=\frac{6-2(x+3)}{x(x+3)}=\frac{-2x}{x(x+3)}=-\frac{2}{x+3}\\\\1b)\; \; \frac{6}{x^2}+\frac{3x-2}{x}=\frac{6+x(3x-2)}{x^2}=\frac{3x^2-2x+6}{x^2}\\\\\\2)\; \; \frac{5b}{a^2-ab}\cdot \frac{a^2-b^2}{10b^2}=\frac{5b}{a(a-b)}\cdot \frac{(a-b)(a+b)}{10b^2}=\frac{a+b}{2\cdot a\cdot b}$