Question

Выполни действия (s2−2s+44s2−1⋅2s2+ss3+8−s+22s2−s):4s2+2s−10s+14−8s.

Answer 1

$\Big(\dfrac{s^2-2s+4}{4s^2-1}\cdot \dfrac{2s^2+s}{s^3+8}-\dfrac{s+2}{2s^2-s}\Big):\dfrac{4}{s^2+2s}-\dfrac{10s+1}{4-8s}=\\\\\\=\Big(\dfrac{s^2-2s+4}{(2s-1)(2s+1)}\cdot \dfrac{s(2s+1)}{(s+2)(s^2-2s+4)}-\dfrac{s+2}{s(2s-1)}\Big)\cdot \dfrac{s(s+2)}{4}-\dfrac{10s+1}{4(1-2s)}=\\\\\\=\Big(\dfrac{s}{(2s-1)(s+2)}-\dfrac{s+2}{s(2s-1)}\Big)\cdot \dfrac{s(s+2)}{4}+\dfrac{10s+1}{4(2s-1)}=$

$=\dfrac{s^2-(s+2)^2}{s(2s-1)(s+2)}\cdot \dfrac{s(s+2)}{4}+\dfrac{10s+1}{4(2s-1)}=\\\\\\=\dfrac{-4s-4}{2s-1}\cdot \dfrac{1}{4}+\dfrac{10s+1}{4(2s-1)}=\dfrac{-4s-4+10s+1}{4(2s-1)}=\dfrac{6s-3}{4(2s-1)}=\\\\\\=\dfrac{3\, (2s-1)}{4\, (2s-1)}=\dfrac{3}{4}$

Answer 2

ответ: во вложении Объяснение: