Question

Разложи на множители:
(t^10+s^10)^2−(t^10−s^10)^2−t^2s^2 .

^ - степень

Answer 1

$(t^{10}+s^{10})^2-(t^{10}-s^{10})^2-t^2s^2=\\\\=t^{20}+2t^{10}s^{10}+s^{20}-(t^{20}-2t^{10}s^{10}+s^{20})-t^2s^2=\\\\=4t^{10}s^{10}-t^2s^2=t^2s^2\, (4\, t^8s^8-1)=\\\\=t^2s^2\, (2\, t^4s^4-1)(2\, t^4s^4+1)=\\\\=t^2s^2\, (\sqrt2\, t^2s^2-1)(\sqrt2\, t^2s^2+1)(2\, t^4s^4+1)=\\\\=t^2s^2\, (\sqrt[4]2\, ts-1)(\sqrt[4]2\, ts+1)(\sqrt2\, t^2s^2+1)(2\, t^4s^4+1)$