- 3/2; 1/6.
Объяснение:
12y² + 16y - 3 = 0
D = b² - 4ac
D = 16² - 4 · 12 · (-3) = 256 + 144 = 400
х1/2 = -b ± √D x1/2 = -16 ± 20
2a 24
-16 - 20 -36 3
х₁ = = = -
24 24 2
-16 + 20 4 1
х₂ = = =
24 24 6
1. выполните умножение:
(x + y)(x - y) = x² - y²
1) (x + y)(x - y) = x² - y²
2) (k - 2)(k + 2) = k² - 4
3) (4 + b)(4 - b) = 16 - b²
4) (1/7 + x)(1/7 - x) = 1/49 - x²
5) (5/6 + m)(5/6 - m) = 25/36 - m²
6) (k + 1,1)(k - 1,1) = k² - 1.21
2. Разложите на множители:
По формуле:
x² - y² = (x - y)(x + y)
1) a² - 49 = (a - 7)(a + 7)
2) c² - 2,25 = 0,25 × (4с² - 9) = 0,25 × (2c - 3)(2c + 3)
3) 64/81 - x² = 1/81 × (64 - 81x²) = 1/81 × (8 - 9x)(8 + 9x)
4) z² - 169/196 = 1/196 × (196z² - 169) = 1/196 × (14z - 13)(14z + 13)
5) 25x² - 36 = (5x - 6)(5x + 6)
6) 0,64 - 1/9z² = 16/25 - 1/9z² = 1/225 × (144 - 25z²) = 1/225 × (12 - 5x)(12 + 5x)
Объяснение:
a) 4a - a³ = a(4-a²) = a (2-a)(2+a)
b) ax² + 2ax + a = a(x² + 2x + 1) = a(x+1)²