Теңдеуді шеш: (2,7y – 2)(y + 2) = (0,3y – 1)(9y – 3) + 3,3y. y = . - id1455403520230524 от arnalismailov 24.05.2023 04:23

Question

Алгебра: Теңдеуді шеш: (2,7y – 2)(y + 2) = (0,3y – 1)(9y – 3) + 3,3y. y = .

arnalismailov · Accepted Answer

B^2 - 9y^2 : 4b^2 +12by+9y^21) 5(x+4y)/ 15(x+4y) = 1/3
2) 8a^2+40ab : ab+5b^2 = 8a (a + 5b) / b(a+5b) = 8a/b
3) 8ab : 4a^2 b^2+8ab^3 = 8ab / 4ab^2 (a +2b) = 2/b (a+2b)
4) x^2 -9 : 4x-12 = (x-3)(x+3) / 4(x-3) = x+3/4
5) 3a+15b : a^2 - 25b^2 = 3(a+5b) / (a-5b)(a+5b) = 3/a+5b
6) y^2+4y+4 : y^2 +2y = (y+2)^2 / y(y+2) = y+2/y
7) b^2 +10b+25 : b^2 -25 = (b+5)^2 / (b-5)(b+5) = b+5/b-5

4b^2 - 9y^2 : 4b^2 +12by+9y^2 = (2b-3y)(2b+3y)/ (2b+3y)^2 = 2b-3y/2b+3y = 2*(-1/4) - 3* (5/6) / 2*(-1/4) - 3*(-5/6) = -0.5 + 2.5 / -0.5 +2.5 = 2/2 = 1

Теңдеуді шеш: (2,7y – 2)(y + 2) = (0,3y – 1)(9y – 3) + 3,3y. y = .

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