Question

хороший ответ отмечаю сразу​

Answer 1

$1)\ \ (a+2)^5=a^5+5a^4\cdot 2+10a^3\cdot 2^2+10a^2\cdot 2^3+5a\cdot 2^4+2^5=\\\\=a^5+10a^4+40a^3+80a^2+80a+32\\\\2)\ \ (a+1)^5=a^5+5a^4+10a^3+10a^2+5a+1\\\\3)\ \ (a+b)^6=a^6+6a^5b+15a^4b^2+20a^3b^3+15a^2b^4+6ab^5+b^6\\\\4)\ \ (a-b)^6=a^6-6a^5b+15a^4b^2-20a^3b^3+15a^2b^4-6ab^5+b^6\\\\5)\ \ (a-2)^5=a^5-10a^4+40a^3-80a^2+80a-32\\\\6)\ \ (a-1)^6=a^6-6a^5+15a^4-20a^3+15a^2-6a+1\\\\7)\ \ (1+b)^7=1+7b+21b^2+35b^3+35b^4+21b^5+7b^6+b^7\\\\8)\ \ (c+1)^6=c^6+6c^5+15c^4+20c^3+15c^2+6c+1$

$9)\ \ (c+2)^5=c^5+10c^4+40c^3+80c^2+80c+32$