Question

решить
1) y2-6y=0
2)7a2-3a=0
3)12m2-4m=0

(Зарание

Answer 1

1

$y {}^{2} - 6y = 0 \\ y \times (y - 6) = 0 \\$

$y = 0 \\ y - 6 = 0$

$y = 0 \\ y = 6$

ответ: y1,y2(0;6)

2

$7a {}^{2} - 3a = 0 \\ a \times (7a - 3) = 0$

$a = 0 \\ 7a - 3 = 0$

$a = 0 \\ a = \frac{3}{7}$

3

$12m {}^{2} - 4m = 0 \\ 4m \times (3m - 1) = 0 \\ m \times (3m - 1) = 0$

$m = 0 \\ 3m - 1 = 0$

$m = 0 \\ m = \frac{1}{3}$