Question

Решите не игнорьте решение нужно просто ответ не пишите​

Answer 1

$\sqrt{6(log_{9}2*log_{4}9+1)+log_{2}9^{-6}+log_{2}^{2}9}=\sqrt{6(log_{9}2*\frac{1}{2}log_{2}9+1)-6log_{2}9+log_{2}^{2}9}=\\\\=\sqrt{6(\frac{1}{2}*\underbrace { log_{9}2*log_{2}9}_{1}+1)-6log_{2}9+log_{2}^{2}9}=\sqrt{6*1,5-6log_{2}9+log_{2}^{2} 9} }=\\\\=\sqrt{log_{2}^{2}9-6log_{2}9+9}=\sqrt{(log_{3}9-3)^{2}}=|log_{2} 9-3|=\boxed{log_{2} 9-3}$

Answer 2

$\sqrt{6( log_{9}2 \times log_{4}9 + 1) + { log_{2}9 }^{ - 6} + { log^{2} _{2}} 9 } = \\ = \sqrt{6( log_{9}2 \times \frac{1}{2 log_{2}9 } + 1) - 6 log_{2}9 +{ log^{2} _{2}} 9 } = \\ = \sqrt{9 - 6log_{2}9 +{ log^{2} _{2}} 9 } = \sqrt{( {3 - log_{2}9) }^{2} } = \\ = |3 - log_{2}9 | = log_{2}9 - 3$