Question

Решите сложения систему уравнений x+3y=11 и 2x+y^2=14​

Answer 1

$\left \{ {{x+3y=11} \atop {2x+y^2=14}} \right.$

$\left \{ {{-2x-6y=-22} \atop {2x+y^2=14}} \right.$

$y^2-6y=-8$

$y^2-6y+8=0$

D $= b^2-4ac = 36-32=4$

$x_{1} =\frac{6+2}{2}=4$

$x_{2} =\frac{6-2}{2} =2$

$\left \{ {{x+3y=11} \atop {x_{1}=4}} \right.$

$\left \{ {{3y+4=11} \atop {x_{1}=4}} \right.$

$\left \{ {{y_{1}=\frac{7}{3} } \atop {x_{1}=4}} \right.$

$\left \{ {{x+3y=11} \atop {x_{2}=2}} \right.$

$\left \{ {{2+3y=11} \atop {x_{2}=2}} \right.$

$\left \{ {{y_{2}=3} \atop {x_{2}=2}} \right.$

ответ: $(4;\frac{7}{3}); (2;3)$