Question

27m9 + A = (3m3 + 2n2)(B – C + 4n4)​

Answer 1

$27m^{9}+\mathbf {8n^{6}}=(3m^{3}+2n^{2})(\mathbf {9m^{6}}-\mathbf {6m^{3}n^{2}}+4n^{4})$

Объяснение:

$a^{3}+b^{3}=(a+b)(a^{2}-ab+b^{2});$

$A=b^{3}=(2n^{2})^{3}=2^{3} \cdot (n^{2})^{3}=8 \cdot n^{2 \cdot 3}=\mathbf {8n^{6}};$

$B=a^{2}=(3m^{3})^{2}=3^{2} \cdot (m^{3})^{2}=9 \cdot m^{3 \cdot 2}=\mathbf {9m^{6}};$

$C=ab=3m^{3} \cdot 2n^{2}=\mathbf {6m^{3}n^{2}};$

$27m^{9}+\mathbf {8n^{6}}=(3m^{3}+2n^{2})(\mathbf {9m^{6}}-\mathbf {6m^{3}n^{2}}+4n^{4});$