(2 + 1)(2^2 + 1)(2^4 + 1)(2^8 + 1)(2^16 + 1) = 2^32 – 1 - id1664929720220730 от О2Л3Я4 30.07.2022 12:33

Question

Алгебра: (2 + 1)(2^2 + 1)(2^4 + 1)(2^8 + 1)(2^16 + 1) = 2^32 – 1

О2Л3Я4 · Accepted Answer

1) sin 152° =sin(180-28)=sin28
2)cos124°=cos(90+34)=-sin34
3)sin242°=sin(270-28)=-cos28
4)cos196°=cos(180+16)=-cos16
5)sin175°=sin(180-5)=sin5
6)cos 235°=cos(270-35)=-cos35
7)tg 111°=tg(90+21)=-ctg21
8) ctg 215°=ctg(180+35)=ctg35
9)sin 312°=sin(270+42)=-cos42
10) cos 166°=cos(180-14)=-cos14
11)sin 290°=sin(270+20)=-cos20
12)ctg 163°=ctg(180-17)=-ctg17
13) tg 286°=tg(270+16)=-ctg16
14)cos 326°=cos(360-34)=cos34
15)sin 221°=sin(180+41)=-sin41
16) cos 306°=cos(270+36)=sin36
17) tg 187°=tg(180+7)=tg7
18) ctg 319°=ctg(360-41)=-ctg41

(2 + 1)(2^2 + 1)(2^4 + 1)(2^8 + 1)(2^16 + 1) = 2^32 – 1

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