Question

Розвяжыть рывняння
(2y-3)(3y+1)+2(y-5)(y+5)=2(1-2y)2+6y

Answer 1

6y²+2y-9y-3+2(y²-25)=4(1-2y)+6y

6y²+2y-9y-3+2y²-50=4-8y+6y

8y²-7y-53=4-2y

8y²-7y-53-4+2y=0

8y²-5y-57=0

8y²+19y-24y-57=0

(8y+19)(y-3)=0

9y+19=0 или y-3=0

y=$-\frac{19}{8}$

y=3

Answer 2

$(2y - 3)(3y + 1) + 2(y + 5) = 2(1 - 2y)2 + 6y$

$6y { }^{2} + 2y - 9y - 3 + 2(y {}^{2} - 25) = 4(1 - 2y) + 6y$

$6y {}^{2} + 2y - 9y - 3 + 2 {}^{2} - 50 = 4 - 8y + 6y$

$8y {}^{2} - 7y - 53 = 4 - 2y$

$8y {}^{2} - 7y - 53 - 4 + 2y = 0$

$8y {}^{2} - 5y - 57 = 0$

$8y {}^{2} + 19y - 24y - 57 = 0$

$y \times (8y + 19) - 3(8y + 19) = 0$

$(8y + 19) \times (y - 3) = 0$

$8y + 19 = 0$

$y - 3 = 0$

$y = - \frac{19}{8}$

$y = 3$

$y1 = - \frac{19}{8}$

$y2 = 3$