Question

Нужно решить пример: 9а кв. - 16в кв. / (3b - 4a - 3b+4a) 7а 4b кв - 3ab 4b кв. + 3ab

Answer 1

$( \frac{3b-4a}{4b^{2}-3ab} - \frac{3b+4a}{4b^{2}+3ab} )=\frac{3b-4a}{b(4b-3a)} - \frac{3b+4a}{b(4b+3a)}= \frac{12b^{2}-16ab+9ab-12a^{2} }{b(16b^{2} -9a^{2} )} - \frac{12b^{2}+16ab-9ab-12 a^{2} }{b(16b^{2} -9a^{2} )} = \frac{12b^{2}-7ab-12a ^{2} -12b^{2}-7ab+12a^{2} }{b(16b^{2} -9a^{2} )} =- \frac{14ab}{b(16b^{2} -9a^{2} )} ; \frac{9a^{2} -16b^{2} }{7a} *- \frac{b(16b^{2} -9a^{2} )}{14ab} ???$