Question

Алгебра
решите под буквами б и г ​

Answer 1

$1)tg(\pi+\alpha)+Ctg( \frac{\pi }{2}-\alpha)=tg\alpha+tg\alpha=\boxed{2tg\alpha}\\\\\\2)\frac{Cos\alpha }{1-Sin\alpha }-\frac{Cos\alpha }{1+Sin\alpha}=\frac{Cos\alpha+Sin\alpha Cos\alpha-Cos\alpha+Sin\alpha Cos\alpha}{(1-Sin\alpha)(1+Sin\alpha)} =\frac{2Sin\alpha Cos\alpha}{1-Sin^{2}\alpha}=\\\\=\frac{2Sin\alpha Cos\alpha}{Cos^{2}\alpha} =\frac{2Sin\alpha }{Cos\alpha }=\boxed{2tg\alpha}$