Question

Решить уравнения sint=1/2 cost=-корень3/2

Answer 1

$sint=\frac{1}{2}\\t=(-1)^n\cdot \frac{\pi}{6}+\pi n,\; n\in Z\\2.\; \; cost=-\frac{\sqrt3}{2}\\t=\pm arccos(-\frac{\sqrt3}{2})+2\pi n\\t=\pm(\pi -arccos\frac{\sqrt3}{2})+2\pi n\\t=\pm (\pi -\frac{\pi}{6})+2\pi n\\t=\pm \frac{5\pi}6}+2\pi n,\; n\in Z$