Question

Кто нибудь по алгебру решить

Answer 1

$\bigg (-24 \ ; \ -213\dfrac{1}{3} \bigg )$

Объяснение:

$\displaystyle \left \{ {{5x-0,6y=8} \atop {2x-0,3y=16}} \right. \Leftrightarrow \left \{ {{5x-0,6y=8} \atop {4x-0,6y=32}} \right. \bigg |- \Leftrightarrow \left \{ {{5x-4x-0,6y+0,6y=8-32} \atop {y=\dfrac{2x-16}{0,3}}} \right. \Leftrightarrow$

$\displaystyle \Leftrightarrow \left \{ {{x=-24} \atop {y=\dfrac{2 \cdot (-24)-16}{0,3}}} \right. \Leftrightarrow \left \{ {{x=-24} \atop {y=\dfrac{-64}{0,3}}} \right. \Leftrightarrow \left \{ {{x=-24} \atop {y=-\dfrac{640}{3}}} \right. \Leftrightarrow \left \{ {{x=-24} \atop {y=-213\dfrac{1}{3}}} \right. ;$

$\bigg (-24 \ ; \ -213\dfrac{1}{3} \bigg );$