Question

1/2+(3m/1-3m+2m/3m+1)*9m2-6m+1/6m2+10m

Answer 1

1$\frac{1}{2} + ( \frac{3m}{1-3m } + \frac{2m}{3m+1} ) * \frac{9m^2-6m +1}{6m^2+10m} = \\ \\ = \frac{1}{2} + \frac{3m(3m+1) -2m (3m-1)}{-(3m-1)(3m+1)} * \frac{(3m-1)^2}{2m(3m+5)} = \\ \\ = \frac{3}{2} + \frac{9m^2+3m -6m^2+2m}{-(3m-1)(3m+1)} * \frac{(3m-1)^2}{2m(3m+5)} = \\ \\ = \frac{1}{2} + \frac{3m^2+5m }{- (3m-1)(3m+1)} * \frac{(3m-1)^2}{2(3m^2+5m)} = \\ \\ = \frac{3m+1}{2(3m+1)} - \frac{2(3m-1)}{3m+1 } = = \frac{-3m+3}{2(3m+1)} = 1.5 * \frac{1-m}{3m+1}$