Hing (178-181): x2 + x - 6 0, + . 2) x2 + x + 6 0. - id2062234020230331 от tamerlana34ovwuq7 31.03.2023 23:03

Question

Алгебра: Hing (178-181): x2 + x - 6 0, + . 2) x2 + x + 6 0.

tamerlana34ovwuq7 · Accepted Answer

B1 + b1q^3 = -49
b1q + b1q^2 = 14 разделим первое уравнение на 2-е
(1 + q^3)/(q +q^2) = -7/2
(1+q)(1 -q +q^2)/q(1 +q) = -7/2
(1 -q +q^2) /q = -7/2
2(1 - q +q^2) = -7q
2 -2q +2q^2 +7q = 0
2q^2 +5q +2 = 0
D = b^2 -4ac = 25 -16 = 9
q1= -1/2, a) b1 + b1q^3 = -49    б) q2 =-2     b1 + b1q^3 = -49
b1 +b1*(-1/8) = -49    b1 + b1*(-8) = -49
7/8 b1 = -49    -7b1 = -49
b1 = -49: 7/8= -49*8/7= =56    b1 = 7

Hing (178-181): x2 + x - 6 > 0, + . 2) x2 + x + 6 >0. ${x}^{2} + x - 6 0$

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